-22x^2-66x+1540=0

Solution for -22x^2-66x+1540=0 equation:

-22x^2-66x+1540=0

a = -22; b = -66; c = +1540;
Δ = b2-4ac
Δ = -662-4·(-22)·1540
Δ = 139876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{139876}=374$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-374}{2*-22}=\frac{-308}{-44}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+374}{2*-22}=\frac{440}{-44}
=-10
$